A body is thrown vertically up with some velocity (at t = 0) crosses a fixed point P in its path at t = 4 s and again at t = 6 s. The velocity of projection of the body will be
a)20 m/s
b) 50 m/s
c) 10 m/s
d) 40 m/s
Answers
Answer:
I don't no the answer but answer is c) 10 m/s
Answer:
The velocity of projection of the body will be 50 m/sec.
Explanation:
What is Velocity ?
Velocity of projection refers to how quickly the projectile is launched. The projectile's numerous characteristics, including its time of flight, range, etc., were primarily governed by its velocity of projection.
Angle of Projection: This refers to the angle at which the projectile is projected with respect to the surface. The projectile's maximum range angle should be 450 degrees. This programme is used for a variety of things to send the particle as far as possible.
The projectile's trajectory is the path it takes after being launched.
The time taken to reach the top from point P = time taken to reach P from top
Therefore , Time of Ascend = 4 + 1 = 5 secs
If the initial and Final velocities are u and v respectivly then
v = u + at
⇒ 0 = u - 10 * 5
[ v = 0 at max height velocity is zero and a = 10 m/sec^2 as accelaration due to gravity is 10 m/ sec^2]
⇒ u = 50 m/sec
b) The velocity of projection of the body will be 50 m/sec.
To learn more about Velocity and Projection refer to :
https://brainly.in/question/12206855?referrer=searchResults
https://brainly.in/question/4436114?referrer=searchResults
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