A body is thrown vertically up with the initial velocity of 30 m\s then its displacement after 6 seconds is
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Question :-
A body is thrown vertically up with the initial velocity of 30 m\s then its displacement after 6 seconds will be ?
Answer :-
-30 m/s
☞ Explanation -
Given -
- Initial Velocity = 0
- final Velocity = 30 m/s
- time = 6 seconds
Solution -
( by using first equation of motion , v = u + at )
➢
v = u + ( - a ) t
u = -a × t + v
u = -10 × 6 + 30
u = -60 + 30
u = - 30 m/s
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☞ Additional information :-
➸ ✔ The three equations of motion that describe the behavior of a physical system in terms of position, Velocity and acceleration as functions of time are :
i) v = u + at
ii) s = ut + ½at²
iii) v² - u² = 2as
➸ ✔ These equations of motion are valid only when the acceleration is constant .
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