Question

a body is thrown vertically upward and takes 5 secs to reach maximum height the distance travelled by the body will be same in
1)1st and 10th second
2)2nd and 8th second
3)4th and 6th second
4)both 2 and 3

Answer 1

It's answer is 1) 1st and 10th second.
But it also may be 5th and and 6th which you have not given in option.
It is law that if a body is thrown vertically upward then the time taken by it in going upward will be same as the time taken to come downward and it travels same distances as it goes upward and comes downward at same time.

<Hope it helps>
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Answer 2

Answer: 1st and 10th second

Explanation:

g=10m/sec  

2

 

V  

0

​

=g×t=70×5=50m/s

from t=0 to t=1sec

h=(V  

0

​

×1−5×10  

2

)−0=50−5=45mup

from t=q to t=10sec

h=[V  

0

​

×10−5×(10)  

2

]−[V  

0

​

×9−5×(9)  

2

]

h=0−450−405

h=−45m

So, 1  

st

 and 10  

th

sec