Question

a body is thrown vertically upward direction with 2m/s and reach maximum height of 10M time in which it reaches to 10 m will be if downward acceleration is 10 m/s​

Answer 1

Answer:

10MS OK BRO

Explanation:

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Answer 2

Answer:

Let H be the maximum height of the ball .

When , the ball is reached one half of the maximum height , then

          u=10m/s,v=0m/s,g=10m/s  

2

 and h=H/2 (remaining height) ,

by using ,    

             v  

2

=u  

2

−2gh  

             0  

2

=10  

2

−2×10×(H/2)

or           H=100/10=10m

Explanation:

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