Question

A body is thrown vertically upward from a point 'A' 125m above the ground. It goes up to a maximum height of 250 m above thevground and passes through 'A' on its downward journey. The velocity of the body when it is at a height of 70m above the ground is (g = 10 m/s2)
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Answer 1

Explanation:

At the hight of 70 m

S(distance)= 250-70=180m

a= 10m/S2

u= 0 m/s

so , v^2=u^2+2as

so,v^2=0^2+2×10×180

=3600

Hence speed at that position = root 3600 = 60 m/s.

Answer 2

Answer:

60 m/s

Explanation:

at position a velocity of ball is 0.

acceleration is 10 m/s^2(approx)

total distance{250} - 70 m = distance traveled ball downward.

As (v^2=u^2+2as)

therefore, v^2=0+2 x 10 x 180

v^2=3600

v=60 m/s

thank you!!