Question

A body is thrown vertically upward from the top a of a tower it reaches the ground in t1 sec. If it is thrown vertically downward from point a with the same speed it reaches ground in t2 sec. If it is allowed to fall freely from a then what is the time taken to reach the ground

Answer 1

Answer:under root t1t2

Explanation:

For upward motion ,

H=1/2gt1'2 {u=0} eq 1

For downward motion of ball

H=1/2gt2'2 eq2

For free fall of the ball

H=1/2gt'2 eq 3

Now,

Multiply t2 in eq 1 and t1 in eq 2

And add them ,

We get ,

h=1/2gt1t2, eq 4

Putting the value of h in eq 3,

1/2gt1t2=1/2gt'2

T=under root t1t2

Hope this will help you .

Also mark it the brainliest answer.

Answer 2

Answer:

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