A body is thrown vertically upward reachen a height of 20m find its initial velocity and the time taken by the body to come back to the earth ( g=10m/s 2)
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Answer:
Time to reach maximum height can be obtained from v=u+at
0=20+(−10)t
t=2s
s=ut+0.5at
2
=20(2)+0.5(−10)(2)
2
=20m
Thus, total distance for maximum height is 45 m
s=ut+0.5at
2
45=0+0.5(10)(t
′
)
2
t
′
=3s
Total time= 3+2= 5s
Explanation:
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