A body is thrown vertically upward, such that the distance travelled in 6th and 7th second of its motion are equal. The velocity with which body was projected from ground is
Answers
When a body is projected upwards it is acted upon by the gravitational force.
The distance it travels in the preceding second is always more than the distance it covers in the next second.
For these distances to be equal, the the object should reach the maximum height in the preceding second.
In our case the object reaches maximum height in the sixth second.
At maximum height the final velocity is 0.
Taking g = 9.8 we have :
V = u - gt
V = 0
0 = u - 9.8 × 6
U = 58.8
The initial velocity is thus :
= 58.8 m/s
Answer:
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Explanation:
When a body is projected upwards it is acted upon by the gravitational force.
The distance it travels in the preceding second is always more than the distance it covers in the next second.
For these distances to be equal, the the object should reach the maximum height in the preceding second.
In our case the object reaches maximum height in the sixth second.
At maximum height the final velocity is 0.
Taking g = 9.8 we have :
V = u - gt
V = 0
0 = u - 9.8 × 6
U = 58.8
The initial velocity is thus :
= 58.8 m/s=60m/s
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