Question

A body is thrown vertically upward which velocity u the greatest height h to which it will rise is

Answer 1

Given:

Initial upward velocity = u

To find:

Max height upto which the ball rises

Concept And Assumption:

We have to assume something before doing this question :

• Gravitational acceleration doesn't change with height

• There is no air drag /air resistance

Now since we have considered gravitational acceleration to be constant , we can easily apply the equation of kinematics to solve this problem.

Calculation:

Considering downwards as negative sign:

Applying 3rd equation of kinematics :

$\therefore \: \: {v}^{2} = {u}^{2} + 2as$

$= > {0}^{2} = {u}^{2} + 2 \times ( - g) \times h$

$= > 0 = {u}^{2} - 2gh$

$= > 2gh = {u}^{2}$

$= > h = \dfrac{ {u}^{2} }{2g}$

So max height reached is u²/2g.

Answer 2

Explanation:

In this way we can do the problem for you my friend