Physics, asked by nasheebdangi6139, 1 year ago

A body is thrown vertically upward with 55 m/s (g = 10 m/s2). Distance travelled by the body in 6th second is

Answers

Answered by ShreyaPandey21
1
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Answered by Jasashmita1
5
HERE IS YOUR ANSWER

GIVEN :-

U=55m/s
g=10m/s^2
t=6 s

h = ut + 1/2 gt^2

55×6+1/2 ×10 ×6^2

55×6 + 1/2×10 ×36

330 + 180

510 m

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