A body is thrown vertically upward with a velocity of 98 m/s. If g=9.8m/s2
,when will it reach its highest
point ?what will be its maximum height?
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Heya !!!
This is your answer.
Given :
u = 98 m/s
g = -9.8 m/s². ( As it is thrown upwards)
v = 0 (As it will stop after reaching heighest point)
Using
2gs = v² - u²
2 × -9.8 × s = - (98 × 98)
s = (98 × 98)/(2 × 9.8)
s = 98 × 5
s = 490 m.
Now, Using
v = u + at
0 = 98 - 9.8 × t
t = 10 s
Hope You Got It
This is your answer.
Given :
u = 98 m/s
g = -9.8 m/s². ( As it is thrown upwards)
v = 0 (As it will stop after reaching heighest point)
Using
2gs = v² - u²
2 × -9.8 × s = - (98 × 98)
s = (98 × 98)/(2 × 9.8)
s = 98 × 5
s = 490 m.
Now, Using
v = u + at
0 = 98 - 9.8 × t
t = 10 s
Hope You Got It
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