A body is thrown vertically upward with a velocity u1.what will be the greatest height 'h' it will rise to? Also find the ratio of displacement to the displacement covered.
Plz it is very urgent..
Plz solve it for 20 pts
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this is the maximum height reached by the body
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muski1606:
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u = u1
v = 0
a = g
v = u + at
0 = u1 + gt
gt = -u1
t = -u1/g
s = ut + 1/2at²
h = u1×u1/g + 1/2×g×u1²/g²
= u1²/g+u1²/2g
= (2u1²+u1²)/2g
h = 3u1²/2g
Displacement till height h = 3u1²/2g
Distance till height h = 3u1²/2g
Ratio = (3u1²/2g)/(3u1²/2g)
= 1:1
v = 0
a = g
v = u + at
0 = u1 + gt
gt = -u1
t = -u1/g
s = ut + 1/2at²
h = u1×u1/g + 1/2×g×u1²/g²
= u1²/g+u1²/2g
= (2u1²+u1²)/2g
h = 3u1²/2g
Displacement till height h = 3u1²/2g
Distance till height h = 3u1²/2g
Ratio = (3u1²/2g)/(3u1²/2g)
= 1:1
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