A body is thrown vertically upward with initial velocity 9.8m/s. It will attain a height:
A. 9.8m
B. 19.8m
D. 29.4m
2.4.9m
Answers
Initial velocity, u = 9.8 m/s
Final velocity, v = 0
Acceleration, a = g = - 9.8 m/s²
To Find,
Height reached , s = ?
According to the 3rd equation of motion,
We know that,
v² - u² = 2gs
So, putting all the values, we get
⇒ v² - u² = 2gs
⇒ (0)² - (9.8)² = 2 × (- 9.8) × s
⇒ 96.04 = - 19.6 s
⇒ 96.04/19.6 = s
⇒ s = 4.9 m.
Hence, the height reached by ball is 4.9 m.
please mark me brain mark list
Answer:
Initial velocity, u = 9.8 m/s
67
Final velocity, v = 0
Acceleration, a = g = -9.8 m/s²
To Find,
Height reached, s = ?
According to the 3rd equation of motion,
We know that,
v²-u² = 2gs
So, putting all the values, we get
→ v²-u² = 2gs
(0)² - (9.8)² = 2 × (- 9.8) * s
→ 96.04 - 19.6 s
→ 96.04/19.6 = s
⇒ s = 4.9 m.
Hence, the height reached by ball is 4.9 m.
please mark me brain mark list