Question

A body is thrown vertically upward with velocity u. the distance travelled by it in the 5th and 6th seconds are equal. The velocity U is given by ( given g=10m/(S2))​

Answer 1

Answer:

Third equation of motion.

2as=v^2-u^2

Answer 2

The body travels same distance in 7th and 8th second. So, it reaches its maximum height in 7s.

After 7s, its initial velocity is zero and it starts to move in the downward direction.

Thus, the displacement in the 8th second is,

s=0+1/2×9.8×(8-7)

=5m