Question

A body is thrown vertically upward with velocity u the greatest height h to which it will rise is. explanation required...​

Answer 1

Explanation:

it will rise to final velocity becomes 0

Answer 2

Answer:

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$\frac{u {}^{2} }{2g}$

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Explanation:

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V = 0

Acceleration due to gravity (a) = – g

S = H

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We know that,

V$^{2}$ = u$^{2}$ + 2as

By substituting the values, we get

0 = u$^{2}$ – 2gH

⟹ 0 = u$^{2}$ – 2gH

⟹ H = u$^{2}$ /2g

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Know more:

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Some useful formulas:

Newton's first equation of motion:

• v = u + at

Newton's second equation of motion:

• s = ut + 1/2 at$^{2}$

Newton's second equation of motion:

• v$^{2}$ = u$^{2}$ + 2as