a body is thrown vertically upward with velocity u tje greatest height h to which it will rise is what
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Answer:
H=(u^2)/2g
Explanation:
At highest point the velocity is zero.
Niw if we take maximum height as H and gravity as g (downward direction), and initial velocity as u and apply 3rd equation of motion:
v^2=u^2+2as
0^2=u^2+2(-g)H
2gH=u^2
H = (u^2)/2g
*g is negative as it is acting downward.
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