Question

. A body is thrown vertically upward with velocity u1, the greatest height 'h; to which it will rise is? *
1 point
u/g
u^2/2g
u^2/g
u/2g

Answer 1

Answer:

u^2/2g

Explanation:

explanation is given in the pic

Answer 2

Answer:

Your answer is u^2/2g

Explanation:

We know v^2=u^2 + 2as

let v=0 (because it will stop when it reach at maximum height)

u=u

a=g( acceleration due to gravity)

s=h

We have to find h

Now, 0^2 = u^2 + 2(-g)h     (g is negative here because body is going up)

     =>0 = u^2 - 2gh

=>  2gh = u^2

=> h = u^2/2g