Question

a body is thrown vertically upward with velocity v, the greatest height h to which it will rise is

(a)
$\frac{u}{g}$
(b)
$\frac{ {u}^{2} }{2g}$
(c)
$\frac{ {u}^{2} }{g}$
(d)
$\frac{u}{2g}$
​

Answer 1

maximum height

$= \frac{u {}^{2} \sin {}^{2} (a) }{2g} \\ = \frac{u {}^{2} \sin {}^{2} (90) }{2g} \\ = \frac{u {}^{2} \times 1}{2g} \\ = \frac{u {}^{2} }{2g}$

option ( b)