Question

a body is thrown vertically upwards and takes 5 sec to reach maximum height.The distance travelled by the body will be same in (1).1st and 10th sec (2).2nd and 8th sec (3).4th and 6th sec (4).both (2) and (3)

Answer 1

1st and 10th second
using g = 10 m/sec^2 :
Vo = g × t = 10 × 5 = 50 m/sec

from t = 0 to t = 1 sec
h = ((Vo × 1-5 × 1^2)-0) = (50-5) = 45 m (up)

from t = 9 to t = 10 sec
h = ((Vo × 10-5 × 10^2)-(Vo × 9-5 × 9^2) = (0-450+405) = -45 m (down)

Answer 2

1 option is right ...their is no need to calculate in this question
bcoz the body travel equal distance while going up and coming down if the time interval is same