Question

a body is thrown vertically upwards and takes 5 seconds to reach maximum height.The distance travelled by the body will be same in
1. 1st and 10th sec
2. 2nd and 8th sec
3. 4th and 6th sec
4. both 2 and 3


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Answer 1

$\huge\underline\mathfrak\blue{a}\underline\mathfrak\orange{n}\underline\mathfrak\purple{s}\underline\mathfrak\green{w}\underline\mathfrak\red{e}\underline\mathfrak\blue{r}$

Both 2 & 3

Answer 2

g=10m/sec^2

Vo =g×t=70×5=50m/s

from t=0 to t=1sec

h=(Vo×1−5×10^2)−0=50−5

=45mup

from t=q to t=10sec

h=[Vo×10−5×(10)^2 ]−[Vo×9−5×(9)^2 ]

h=0−450−405

h=−45m

So, 1 st and 10 th sec is the answer