Question

A body is thrown vertically upwards from the top of a tower from point
a. it reaches the ground in time t1. if it is thrown vertically downwards from a with the same speed, it reaches the ground in time t2, if it is allowed to fall freely from a, then the time it takes to reach the ground is given by

Answer 1

Answer:

t = √(t₁t₂)

Step-by-step explanation:

Let say Ball thrown with Speed V

thrown vertically downwards with V it reaches the ground in time t₂

S = Vt₂ + (1/2)g(t₂)²

thrown vertically upwards from the top of a tower it reaches the ground in time t1

Time taken to come at same point = t₁ - t₂

Time taken to teach top = (t₁ - t₂)/2

Velocity at top = 0

0 = V - g(t₁ - t₂)/2

=> V = g(t₁ - t₂)/2

S = t₂g(t₁ - t₂)/2 + (1/2)g(t₂)²

S = gt₁t₂/2

if fall freely then

S = (1/2)gt²

Equating both

(1/2)gt² = gt₁t₂/2

=> t² = t₁t₂

=> t = √(t₁t₂)

Answer 2

Answer:

hey plz check the attachment

Thank u ❤