Question

A body is thrown vertically upwards reaches a maximum height 'h', it returned to the ground the distance travelled will be

Answer 1

According to the question , A particle has been thrown vertically upwards. The object reaches a maximum height of h after which its velocity becomes zero. Because of gravity acting downwards , it again comes back to the ground.

To find:

Distance travelled by the object

Concept:

Distance is a scalar quantity representing the total path length traveled by an object. It only has magnitude and no direction

So , let distance be d :

$d = h \: + \: h \: = 2h$

So final answer :

2h distance has been travelled by object.

Answer 2

$\Large\displaystyle{\underline{\tt{GIVEN:-}}}$

A body is thrown vertically upwards which reaches a maximum height 'h'.

$\Large\displaystyle{\underline{\tt{TO\ DETERMINE:-}}}$

The distance travelled by the body.

$\Large\displaystyle{\underline{\tt{ACKNOWLEDGEMENT:-}}}$

Distance is defined as the total length of the path covered from the initial point to the final position.

$\Large\displaystyle{\underline{\tt{SOLUTION:-}}}$

According to the question,

The body covers a distance of 'h' units while moving up. So, we can say that, the body covers the same distance while coming down too.

So, we conclude that,

Total distance covered = h + h

⇒Total distance covered = 2h

Thus, the object covers a distance of 2h units in an overall.