A body is thrown vertically upwards with a speed of 100 m/s. On the return journey, the speed in m/s at the starting point will be
A) 100 m/s
B) 9.8 m/s
C) 100 x 9.8 m/s
D) 100/9.8 m/s
Answers
Answered by
6
Answer:
Opt A - 100 m/s
Step-by-step explanation:
The quetion simply asks the final velocity
Let final velocity - v m/s
At the top point of its journey, it's velocity is zero, u = 0 m/s
Acceleration - a = 9.8 m/s^2
Time it takes to to go from top point to bottom point will be half of total time taken for journey.
Time taken for whole journey is given by
2u/g, thus to reach from top point to bottom, it will be u/g = 100/9.8 s
Time = 100/9.8
By the first equation of motion,
v = u + at
v = 0 + 9.8 × 100/9.8
v = 100 [ As 9.8 and 9.8 gets cancelled ]
Hope this helps you understand
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Answered by
0
Answer:9.8
Step-by-step explanation:
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