Question

A body is thrown vertically upwards with a speed of 14m/s.Calculate(i)the height to which it rises,and (ii)the time taken by the body to reach the highest point​

Answer 1

To Find:-

• Find the height to which it rises and time taken by the body to reach highest point.

Given:-

• A body is thrown vertically upwards with a speed of 14m/s.
• The gravitational force is -10m/s² because it's going far from ground.
• The final velocity is 0 because the body comes to rest after traveling some distance.

Solution:-

As We know that:-

Here,

u = initial velocity

v = final velocity

g = gravitational force

s = distance

t = time

Now,

u = 14m/s ; v = 0 ; g = -10m/s²

$\text{⟹ \: \: v \: = \: u \: + \: gt}$

$\text{⟹ \: \: 0 \: = \: 14 \: + \: ( -10 )( t )}$

$\text{⟹ \: \: 0 \: = \: 14 \: - \: 10t}$

$\text{⟹ \: \: -14 \: = \: -10t}$

$\text{⟹ \: \: t \: = \: 14/10}$

$\text{⟹ \: \: t \: = \: 7/5}$

$\tt\implies\boxed {t \: = \: 1.4 sec \: }$

Now,

$\text{⟹ \: \: s \: = \: ut \: + \: 1/2 × gt² }$

$\text{⟹ \: \: s \: = \: 14( 1.4 ) \: + \: 1/2 \: × \: -10 \: × \: 1.4 \: × \: 1.4 }$

$\text{⟹ \: \: s \: = \: 19.6 \: + \: 9.8}$

$\tt\implies\boxed {s \: = \: 29.4m \: }$

Answer 2

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

To Find:-

Find the height to which it rises and time taken by the body to reach highest point.

Given:-

A body is thrown vertically upwards with a speed of 14m/s.

The gravitational force is -10m/s² because it's going far from ground.

The final velocity is 0 because the body comes to rest after traveling some distance.

Solution:-

As We know that:-

Here,

u = initial velocity

v = final velocity

g = gravitational force

s = distance

t = time

Now,

u = 14m/s

v = 0

g = -10m/s²

⟹v = u + gt

⟹0 = 14 +(-10)(t)

⟹0 = 14 - 10 t

⟹10 t = 14

⟹t = 14/10

⟹t = 7/5

⟹t = 1.4 sec

Now,

⟹s = it +1/2 × gt²

⟹s = 14(1.4)+1/2×-10×1.4×1.4

⟹s = 19.6 + 9.8

⟹s = 29.4m

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♦ llBrainPowerll ♦