Question

A body is thrown vertically upwards with a velocity of 40 m/s. Calculate its position after 1.5 s and 3 s. Also calculate the velocity and position of the body after 3 s.

Answer 1

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Answer 2

Position of body after 1.5 sec = 48.75 m

Position of body after 3 sec = 75 m

velocity of body after 3 sec = 10 m/s

Explanation:

• Whenever a body is thrown vertically upward it moves against the gravitational force or acceleration due to gravity.
• In upward motion acceleration due to gravity is taken as negative

                 a = -g

Given, initial velocity of body = 40 ms⁻¹

time = 1.5 sec and 3 sec

we can calculate the position by using following equation of motion

=> s = u t+ $\frac{1}{2}$ at²

After 1.5 sec

=> s = 40 * 1.5 + $\frac{1}{2}$ (-10) (1.5)²

=> s = 60 - 11.25

=> s = 48.75 m Position of particle after 1.5 sec

After 3 sec

=> s = 40* 3 +$\frac{1}{2}$ (-10) (3)²

=> s = 120 - 45

=> s = 75 m      Position of particle after 3 sec

Velocity of particle can be calculated by v= u+at

=> v = 40 + (-10) 3

=> v= 40 -30

=> v = 10 ms⁻¹

To know more about vertical motion, visit:

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