English, asked by Aryandamor004, 5 months ago

A body is thrown vertically upwards with a velocity of 40 m/s . Find the maximum height reached by the object also determine the time taken to reach this height . ( g = 10 m/ s2) *
5 sec , 100m
4 sec , 80m
5 sec , 120m
4 sec , 90 sec​

Answers

Answered by snehitha2
23

Answer:

  • The maximum height reached by the object is 80 m
  • The time taken to reach the maximum height is 4 sec

Explanation:

Given :

A body is thrown vertically upwards with a velocity of 40 m/s

To find :

  • the maximum height reached by the object
  • the time taken to reach maximum height

Solution :

initial velocity, u = 40 m/s

acceleration, a = -g = -10 m/s²

At the maximum height,

velocity, v = 0 m/s

Let the maximum height be h m

From the third equation of motion,

v² - u² = 2as

Substitute the values,

0² - 40² = 2 × (-10) × h

-1600 = -20h

  h = 1600/20

  h = 80 m

∴ The maximum height reached by the object is 80 m

Time taken to reach the maximum height = t sec

From the second equation of motion,

S = ut + ¹/₂at²

Substitute the values,

80 = 40t + ¹/₂ × (-10) × t²

80 = 40t - 5t²

5t² - 40t + 80 = 0

5(t² - 8t + 16) = 0

t² - 8t + 16 = 0

t² - 4t - 4t + 16 = 0

t(t - 4) - 4(t - 4) = 0

(t - 4) (t - 4) = 0

⇒ t - 4 = 0 ; t = 4

(OR)

From the first equation of motion,

v = u + at

Substitute the values,

0 = 40 + (-10)t

0 = 40 - 10t

10t = 40

 t = 40/10

 t = 4 sec

∴ The time taken to reach the maximum height is 4 sec

Answered by aryansmore
0

Answer:

t=4s

Explanation:

this is the answer for this question

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