Question

A body is thrown vertically upwards with a velocity of 49 m/s. Calculate :
(i) the time taken by the body to reach the maximum height
(ii) maximum height reached by the body
(iii) time taken by body to hit the ground after it starts is downward motion from the maximum height attained.
(iv) The velocity of the body with which it hits the ground. ​

Answer 1

Answer:

use the equations :

v=u+at

v^2-u^2=2as

s=uh+½at^2

and put the given values in it ,

to find the answers