Physics, asked by shantanues234, 1 year ago

A body is thrown vertically upwards with an initial velocity of 20 m/sec from the ground. Find the speed of the ball when it reaches half of the maximum height.Take g=10 m / sec2
(A) 2 m/s (B) 200 m/s
(C) 10 2 m/s (D) 30 m/s

Answers

Answered by azizalasha
12

Answer:

v = 10√2 m/s

Explanation:

h = u²/2g = 20²/20 = 20 m

h/2 =  10 m = (u² - v² )/2g

v² = 200

v = 10√2 m/s

Answered by harshtanwar80
13

Answer is given below

Attachments:
Similar questions