A body is thrown vertically upwards with an initial velocity of 20 m/sec from the ground. Find the speed of the ball when it reaches half of the maximum height.Take g=10 m / sec2
(A) 2 m/s (B) 200 m/s
(C) 10 2 m/s (D) 30 m/s
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Answered by
12
Answer:
v = 10√2 m/s
Explanation:
h = u²/2g = 20²/20 = 20 m
h/2 = 10 m = (u² - v² )/2g
v² = 200
v = 10√2 m/s
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