Question

A body is thrown vertically upwards with an initial velocity of 20m/s from the ground. Find the speed of the ball when it reaches half of the maximum height.(take g= 10m/s^2)​

Answer 1

Answer:

Explanation:

since velocity is 20 m/s total distance it will cover is 20 m

and maximum height attained by it will be 10 m

so half of max height = 5 m

so now use the formula v^2 = u^2 +2as

V^2 = (20)^2+2* (-10)*5

 V^2  =   300

V = 10√3 m/s =  17.1 m/s