A body is thrown vertically upwards with velocity 'u' and the ratio of potential & kinetic energies is 1:1 at a point 'p'.if it is projected with double the velocity,the ratio of potential & kinetic energies at the same point will be?
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Let a point where,
2
1
mv
2
=mgh
Total M.E=2mgh
Now, when v is twice
Total M.E=8mgh
Now when the ball passes through that point
K.E=8mgh−mgh =7mgh
P.E=mgh
P.E:K.E=1 : 7
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