A body is thrown vertically upwards with velocity u .the distance travelled by it in the fifth and the sixth
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hi!!!
here is Ur answer.
initial velocity=u
final velocity=0 because at certain height it will stop.
1case:if it is 6seconnd.
s=ut+1/2atsquare
s=u×6+1/2×(-9.8)×6×6
s=6u+(-4.9)×6×6
s=6u+(-4.9)x36
s=6u+176.4
hi my sweet friend u replace next case time with 5second.
here is Ur answer.
initial velocity=u
final velocity=0 because at certain height it will stop.
1case:if it is 6seconnd.
s=ut+1/2atsquare
s=u×6+1/2×(-9.8)×6×6
s=6u+(-4.9)×6×6
s=6u+(-4.9)x36
s=6u+176.4
hi my sweet friend u replace next case time with 5second.
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