Question

a body is thrown vertically upwards with velocity u, what is the greatest height h, to which it will rise? class 9 physics motion

Answer 1

Answer:

Explanation:

At highest point v=0

Therefore applying the equation:-

V²=U²+2as

(a=-g ,s=h ,v=0)

U²=2gh

H=U²/2g

Answer 2

We know that:

If a body is thrown vertically upwards with initial velocity (u)

Maximum height of body = $\sf{ \frac{ {u}^{2} }{2g}}$

As:

$\boxed{\sf{2gh = {v}^{2} - {u}^{2}}}$

At maximum height final velocity of body is zero.

So: v = 0

Now:

$\implies$ $\sf{2gh = {v}^{2} - {u}^{2}}$

$\implies$ $\sf{2gh = - {u}^{2}}$

$\implies$ $\sf{h = \frac{ - {u}^{2} }{2g} }$

We know that:

Distance can't be negative.

Therefore:

Answer: $\boxed{\sf{h = \frac{ {u}^{2} }{2g}}}$