Question

a body is thrown vertically upwardswith an initial velocity u.write expression for the maximum height attained by the body

Answer 1

Since the body is thrown vertically upwards, the body after reaching the maximum height will come fo rest, i.e. final velocity of body will become zero, v = 0.

By applying 3rd eq. of kinematics,

v^2 - u^2 = 2as

In case of free fall or throw, it becomes-

v^2 - u^2 = 2gh

0 - u^2 = 2gh

-u^2 = 2(-g)(h) [g is taken as -ve because the body is accelerating against gravity]

Therefore, h(max) = u^2/ 2g [-ve sign cancelling out from both sides]

So, h max. = u^2÷2g or u^2/2g

Answer 2

Answer:

ans is 0

Explanation:

because at hmax velocity is always "0"