Question

a body is thrown veryically upwards and rises to a height of 10m. the velocity with which the body was thrown upwards is (g=9.8m/m2

Answer 1

GIVEN,

  DISTANCE (h) = 10 M.

  ACCELERATION DUE TO GRAVITY (g) =- 9.8 M/S2.

  INITIAL VELOCITY (u) = ?

  FINAL VELOCITY (v) = 0

  TIME TAKEN (t) =?

BY 3RD EQUATION OF MOTION FOR FREELY FALLING BODIES,

  WE GET,

  v2 = u2 + 2 gh

  (0)2= u2 + 2 X -9.8 X 10

  0 = u2 - 19.6 X 10

  0 = u2 - 196

  196 = u2

  (14)2= u2

  THEREFORE,

  u = 14 M/S.

BY 1ST EQUATION OF MOTION FOR FREELY FALLING BODIES,

  WE GET,

      v = u + gt

  0 = 14 - 9.8 X t

  0 = 14 -(9.8 X t)

  0 = 14 - 9.8t

  9.8t = 14

  t = 14/9.8

  t = 1.429 SECS.

   HOPE IT WORKS...!!!!