Question

A body is thrown with a velocity (4^i + 3^j)
metre per second. Its maximum height is [g = 10m/s2]

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Answer 1

Given :-

Initial velocity of body = (4î + 3j) ms-¹

Acceleration due to gravity = g = 10 ms-².

To find

Maximum height attained by the body.

Let the height attained by the body = H.

Resultant of Velocity = √(4)² + (3)²

|u| = √16 + 9

|u| = 5 ms-¹

Using third equation of Motion,

v² - u² = 2gh ( Considering upward motion as negative).

- (5)² = 2 × (-10) H

-25 = - 20 H

H = 25/20

H = 1.25 m

Hence,

The height attained by body = H = 1.25 m

Answer 2

Explanation:

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