a body is thrown with a velocity equal to n (> 1) times the escape velocity (ve) from earth surface. velocity of the body at a very large distance away will be?
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conservation of mechanical energy...
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Answered by
32
since no external force act on the system , mechanical energy remains constant .
thus
Ui + Ki= Kf
-GMm/R + 1/2*m*(n*ve)²=1/2mv²
v=√[-2GM/R+n²ve²]
since ve=√(2GM/R)
v=√(n²-1)ve
thus
Ui + Ki= Kf
-GMm/R + 1/2*m*(n*ve)²=1/2mv²
v=√[-2GM/R+n²ve²]
since ve=√(2GM/R)
v=√(n²-1)ve
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