Question

A body is thrown with a velocity of 40 m/s in a direction making an angle of 300 with the horizontal.

Calculate

i) The horizontal range​

Answer 1

Answer:

300°v angle HOTA hay projectile may....xd

taking it 30°

the horizontal range is

=

$\frac{40 {}^{2} \sin(60) }{9.8} \\ = 141.39 \: \: \: metre$