Question

a body is thrown with an initial velocity root3i + 1j its angle of projection is
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Answer 1

Answer:

m/s

Angle of projectile  tanθ=310

⟹  sinθ=10910  and  cosθ=1093

Maximum height attained   H=2gu2sin2θ

∴    H=2(10)109×109100=5m

Horizontal range   R=gu2sin2θ=g2u2sinθcosθ

⟹   R=102(109)×10910×1093=6m