Physics, asked by tiwariria1318, 7 months ago

a body is thrown with an initial velocity root3i + 1j its angle of projection is

Answers

Answered by gurjot73030

2

Answer:

m/s

Angle of projectile tanθ=310

⟹ sinθ=10910 and cosθ=1093

Maximum height attained H=2gu2sin2θ

∴ H=2(10)109×109100=5m

Horizontal range R=gu2sin2θ=g2u2sinθcosθ

⟹ R=102(109)×10910×1093=6m

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