Question

A body is thrown with the velocity u = 12.0 ms-' at an angle of alpha = 45° to the horizon. It touches to the ground at the distance s from the point where it was thrown. From what height h should stone be thrown in a horizontal direction with the same initial velocity u so that it falls at the same spot?
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Answer 1

Answer:

Explanation:

u = 12 m/s

alpha = 45 degree

s = u^2.sin.2alpha/g

s = 12*12*sin90/9.8

Therefore, s = 14.6m.

Now,    H = u^2sin^2alpha/2.g

12*12.1/under root2^2/2*9.8

72/19.6

= 3.67m.