Question

A body is thrown with velocity of 49 m s^-1 at an angle of 30° with the horizontal, time required to attain maximum height is

(A) 5s

(B) 4s

(C) 3.5s

(D)2.5s​

Answer 1

Answer:

The required to attain maximum height will be 2.45 s

Explanation:

As given, The body is thrown with 49 m s^-1 velocity at an angle of 30° degree

Velocity in the vertical direction will be 49 sin30° = $\frac{49}{2}$

and the acceleration due gravity will be 10 m ^-2

as at the highest point velocity becomes zero so the final velocity is zero

Use the equation v = u +at

                             o = $\frac{49}{2}$-10t

                             -$\frac{49}{2}$= -10t

                             $\frac{49}{20}$ = t

                            2.45 s =t

Answer 2

Answer:

The required to attain maximum height will be 2.45 s

Explanation:

As given, The body is thrown with 49 m s^-1 velocity at an angle of 30° degree

Velocity in the vertical direction will be 49 sin30° = \frac{49}{2}

2

49

and the acceleration due gravity will be 10 m ^-2

as at the highest point velocity becomes zero so the final velocity is zero

Use the equation v = u +at

o = \frac{49}{2}

2

49

-10t

-\frac{49}{2}

2

49

= -10t

\frac{49}{20}

20

49

= t

2.45 s =t

Explanation:

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