Question

A body is tied at the end of a string of length (l) and rotated in a vertical circle .the strin is taut when the body is at highest position.velocity of the body when string is in horizontal position?

Answer 1

applying energy conservation

1/2mu^2=mgl+1/2mv^2

we get v=root(u^2-2gl)

in vector form we can express as v vector=root(u^2-2gl)j and u vector =ui

difference is v-u =root(u^2+v^2)=root(2(u^2-gl))

Answer 2

Answer:

applying energy conservation

1/2mu^2=mgl+1/2mv^2

we get v=root(u^2-2gl)

in vector form we can express as v vector=root(u^2-2gl)j and u vector =ui

difference is v-u =root(u^2+v^2)=root(2(u^2-gl))

Step-by-step explanation:

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