Question

A body is tied to one end of a string and made to revolve in
verticle. Derive expression for the tension in the string at any point.
Hence show that the difference between them tension at lowest
point and highest is six times the weight of the body.​

Answer 1

Answer:

Explanation:

T = m/r (u2 -3gh + gr)  

Explanation:

Let the velocity of the body denoted by 'v' at the vertical circle's point P. Let us assume that the lowest point is denoted as L. At L, the velocity is 'u'.  

By the conservation of energy:  

At point P, the energy is = Energy at point L  

½ mv2 + mgh = ½ mu2  

V2 + 2gh = u2    

At point P, let us consider the centripetal force:    

T - mgcosϴ = mv2/r ------ Equation (1)  

When the values are substituted in equation (1), we obtain:    

T = m/r (u2 -3gh + gr)  

To learn more:    

1. Explain motion in a vertical circle. Obtain expression for velocity and tension in string when body moves in vertical circle: brainly.in/question/7431024  

2. A body of 1kg is suspended by string. the tension in thread if the body moves ip with an acceleration of 5 m/s^2 is (g=10m/s^2)?: brainly.in/question/11765442