Question

A body is traveling along a straight path transversed one third of the total distance with a velocity of 4m/s . The remaining part of the distance was covered with velocity of 2m/s for half the time and with velocity of 6m/s for the other half of the time . What is the average velocity?

Answer 1

Answer:

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Explanation:

Let the total distance be 3x m

First x metres:

 time  taken  travel first x metres = displacement/velocity

                                                       =  x / 4 s      

Let second and third part was covered in 2t seconds.

   distance covered with velocity of 2m/s = t * 2 = 2t seconds

  distance covered with the velocity of 6m/s = 6 * t = 6t seconds

Now, 2t +6t = 2x

           8t = 2x

           4t = x

it means, total distance 3x = 12t

Also, time taken to cover first part= x/4 = t seconds

Average velocity = Total distance covered/ time taken to cover the distance

                            = (12t)/(t+2t)

                            = 12t/3t = 4 m/s