Question

A body is travelling with a constant acceleration of 10m/ s2 . if s1 is the distance trqveled in first second and s2 is the distance traveled in 2nd second, the correct relationship between s1 and s2 is?
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Answer 1

Answer:

Assume starting from rest and a=10m/s^2

S(1)=(1/2)10 t^2=5(1)^2=5m

After 2 seconds, S=(1/2)10(2)^2=20m

So, S(2) is 15 m. And S(2)/S(1)=15/5=3/1

If you keep going, you’ll find the distances traveled in each successive second are in the ratio 1:3:5:7 etc.

As I recall, I think Galileo 1st pointed this out!

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Answer 2

Explanation:

we applied formula Snth=vi+a/2(2n-1)

S1=0+10/2(2×1-1)

S1=5

S2=0+10/2(2×2-1)

15=S2

now if we compare both

5:15 we get 1:3

so relationship should be 1(S1)=3(S2)