a body is travelling with a speed of 10 M per second into North it changes its direction to West without changing its Speed the time taken for entire process is 5 seconds find the average acceleration
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2
Dear
Your answer is
Now change in velocity is equal to magnitude V2-V1 = √(V1²+V2²- V1V2cos90) = √(10²+10²-100cos90) = 10√2
So acceleration = (V2-V2)/t
=> (10√2)/5 = 2√2 = 2.42 m/s²
Hope it helps you
If problem continues ask
Thank you
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Your answer is
Now change in velocity is equal to magnitude V2-V1 = √(V1²+V2²- V1V2cos90) = √(10²+10²-100cos90) = 10√2
So acceleration = (V2-V2)/t
=> (10√2)/5 = 2√2 = 2.42 m/s²
Hope it helps you
If problem continues ask
Thank you
Please Mark it as brainliest !!
shaym1210:
busy with holiday homeworks !!!
great !
don't you go to tourist place this summer ??
how can i go ??
i have so many work
Answered by
1
speed + acceleration = distance/time+f/m
10 + acceleration = (speed×time)/time + f/m
10 + acceleration = 50/5+f/m
10 + acceleration = 10 + force/ mass
10+10 = force/mass + acceleration
20 = f+a×m/m
20m = f+a×m
20m/m = f+ a
20 = f+a
20 = f+f/m
20m = m×f+f
20m/m = f+f
20 = 2f
f = 20/2
f =10
hope it helps
10 + acceleration = (speed×time)/time + f/m
10 + acceleration = 50/5+f/m
10 + acceleration = 10 + force/ mass
10+10 = force/mass + acceleration
20 = f+a×m/m
20m = f+a×m
20m/m = f+ a
20 = f+a
20 = f+f/m
20m = m×f+f
20m/m = f+f
20 = 2f
f = 20/2
f =10
hope it helps
ur ans is incorrect
i ask average acceleration
From where you get force in this question
??
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