A body is uniformly accelerated from 10 m/s to 20m/s in 4 second. Find the distance travelled
Answers
Answered by
2
Answer:
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Explanation:
Explanation:
The initial velocity is
u
=
0
m
s
−
1
The acceleration is
a
=
10
m
s
−
2
The time is
t
=
5
s
Apply the equation of motion
v
=
u
+
a
t
The velocity is
v
=
0
+
10
⋅
5
=
50
m
s
−
1
The distance travelled in the first
5
s
is
s
=
u
t
+
1
2
a
t
2
=
0
⋅
5
+
1
2
⋅
10
⋅
5
2
=
125
m
The distance travelled in the following
10
s
is
s
1
=
v
t
1
=
50
⋅
10
=
500
m
The total distance travelled is
d
=
s
+
s
1
=
125
+
500
=
625
m
Answered by
7
Answer:
60 m
Explanation:
Acceleration = (v - u)/t
= 10/4 = 2.5 m s^-2
According to the 3rd equation of motion, s = (v^2 - u^2)/2a
= (400 - 100)/5
= 300/5
= 60 m
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