A body is vibrating with simple harmonic motion of amplitude 120mm and frequency 5cps.calculate the maximum velocity and acceleration of the body.
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Answer:
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Answer:
given
simple harmonic motion=simple harmonic motion is a special type of periodic motion where the restoring force on the moving object is directly proportional to the magnitude of the object's displacement and acts towards the object's equilibrium position
angular momentum=the quantity of rotation of a body, which is the product of its moment of inertia and its angular velocity
the amplitude of oscillation is 1.2m
a=1.2m
the frequency of simple harmonic motion is 5cps
f=5hz
the velocity of oscillation of the particle is
v=aω
v=a×2πn
v=1.2×2π×5=37.68m/s
the acceleration of the particle is given by
acceleration, A=ω^2×a
A=15×15×1.2
therefore A= 270m/s2
the maximum velocity of the particle is 37.68m/s
the acceleration of the particle is = 270m/s
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