Question

A body is with a velocity of 12m/s and it comes to rest in 18m,what was the acceleration

Answer 1

hey dear
here is your answer

given data :

initial velocity (u) = 12 m/s

final velocity (v) = 0

distance (s) = 18 meter

to find : acceleration (a)

here we go

solution :

by using third equation oif motion

v² = u²+2as

but we use negative sign in front of acceleration as body ius retarding

0 = (12)²-2*a*18

36a = 144

a = 4 m/s²

hope it helps :)

Answer 2

Hey here is your answer
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$Initial velocity (u) = 12 \: m {s}^{ - 1} \\ Final velocity (v) = 0 \: m {s}^{ - 1} \\ Displacement (s) = 18 \: m\\ Acceleration (a) = a \\ \\ then. \\ {v}^{2} = {u}^{2} + 2as \\ \\ {0}^{2} = {12}^{2} + 2 \times a \times 18 \\ \\ 0 = 144 + 36a \\ \\ 36a = - 144 \\ \\ a = - \frac{144}{36} \\ \\ a = - 4 \: m {s}^{ - 2}$
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