Question

A body is without slipping on a horizontalbsirface and its rotational kinetic energy is equal to the transitional kinetic energy the body is

Answer 1

Answer:

Ring

Explanation:

Translational Kinetic Energy = 1/2 mv^2

Rotational Kinetic Energy = 1/2IW^2

I = MR^2 and W = V/R

So 1/2 MR^2( V^2/R^2)

which is 1/2 mv^2 which is equal to translational kinetic energy.