a body just slides on an inclined plane whose base is 12cm height is2.5cm the coefficient of friction is
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The component of force of gravitation for a body of mass m along the inclined surface making an angle Ф with the horizontal is : Fg = m g Sin Ф
The force of static friction Ff just equals Fg as the body just starts to slide down.
Ff = μ N = μ m g Cos Φ = Fg = mg Sin Φ
Hence, μ = coefficient of static friction = Tan Φ = 2.5 cm / 12 cm = 0.2083
The force of static friction Ff just equals Fg as the body just starts to slide down.
Ff = μ N = μ m g Cos Φ = Fg = mg Sin Φ
Hence, μ = coefficient of static friction = Tan Φ = 2.5 cm / 12 cm = 0.2083
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